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Working over $\mathsf{ZF}$, suppose that $X$ is a transitive model of second-order $\mathsf{ZF}^-$, the theory obtained from the second-order $\mathsf{ZF}$ by removing Powerset and adding the second-order Collection. Then do we have $X=H(\kappa)$ for $\kappa=\mathrm{Ord}\cap X$?
Here we define $H(\kappa)$ by the set of all $x$ such that there is no surjection from $\operatorname{trcl}(x)$ to $\kappa$. $H(\kappa)$ is a set by [AK21]. Note that $\kappa$ is regular:
Proof. Suppose that $\kappa$ is singular and $f\colon \alpha\to\kappa$ is a cofinal map such for some $\alpha<\kappa$. Then $\alpha\in X$, and by the second-order Replacement, the image of $f$ is a member of $X$. Thus $X$ thinks there is a cofinal set of $\mathrm{Ord}$, but $\mathsf{ZF^-}$ proves there is no such set.
Also, if $X$ is any model of second-order $\mathsf{ZF}^-$, then $X$ is well-founded, thus we can consider its Mostowski collapse instead.
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Can we find a better upper bound for the consistency strength of $\mathsf{ZF^-}_j$ with $j\colon V\to V$? How about with the cofinality of $j$? The current upper bound for $\mathsf{ZF^-}_j$ with $j\colon V\to V$ is $\mathsf{ZFC}$ with $\mathrm{I}_1$, but I believe we can derive a sharp bound in terms of $\mathsf{KM}$ with a form of Wholeness axiom. Regarding the cofinality of $j$, there is no known bound in terms of $\mathsf{ZFC}$ with large cardinals.
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Does $\mathsf{Con(ZF+WA)}$ prove $\mathsf{Con(ZFC+WA)}$?
This problem is related to how to force Choice while preserving very large cardinals, usually beyond supercompactness.
(A comment added on 2024/06/21) I guess the answer is yes. It should follow from modifying Goldberg’s argument on the following linked MO answer.
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Working over $\mathsf{ZF^-}_j$ with a cofinal elementary embedding $j\colon V\to V$ with a critical point $\kappa$. Then does the successor cardinal $\lambda^+$ of $\lambda=j^\omega(\kappa)$ exist?
Matthews [M22] proves $\mathsf{ZFC}^-_j$ with $j\colon V\to V$ cannot be cofinal if $V_\kappa$ exists. Hayut (on the last day of CHEESE, unpublished, but see [J24]) proved that the cofinal $j$ does not exist even if we do not assume the existence of $V_\kappa$.
(A comment added on 2024/06/21) My recent work [J24] claims the consistency of $\mathsf{ZF}^-$ with a cofinal Reinhardt embedding follows from $\mathsf{ZFC}$ with I0.
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Is there any good way to produce a model of $\mathsf{ZF}^-_j$ with $j\colon V\to V$ from $\mathsf{ZF}$ with a Reinhardt cardinal? Currently, there is no known way for it.
As an associated question, we may ask the following: Suppose that there is a Reinhardt cardinal (or rank Berkely cardinal). Then do we have a proper class of regular cardinals $\gamma$ such that $H(\gamma)$ is a model of second-order $\mathsf{ZF^-}$?